1.A + B +C =
30cm, A + B = 20 Cm. Find B + c ?
2.If we add 10 to twice a number we get 50. Find the number
3.If we subtract 30 from three times a number, we get 100. Find
the number.
4.Find a number which when multiplied by 8 and then reduced by 4 is equal to 64.
5. Sum of two numbers is 100. If one exceeds the other b 5, find the numbers.
6.Sum of three consecutive integers is 27. Find the integers.
7.Find x length 5x+4 and breath x-4 of the rectangle if its perimeter is 72m.
8. After 20 year. Rama’s age will become four times that of he present age. Find he present age.
9.length of a rectangle exceeds its breadth by 5m. If the perimeter of the rectangle is 100m. Find its length and breadth.
10.Rama Said “multiplying my number by 10 and adding 20 to it gives the same answer subtracting my number from 40. Find Rama’s number.
11. A number is divided into two parts such that one part is 20 more than the other. if the two parts in the ration 4: 5 Find the number and the two parts.
12.A sum of Rs. 5000 is to be given in the from of 75 prizes. If the prize money is either Rs 100 or Rs. 25. Find the number of prizes of each type.
13. x0 + 2x0 + 3x0 = 180 Find three angles
14. I am a number Tell my identity Take me two times over and add a forty six To reach a century You still need five.
15.The teacher tells the class that the highest marks obtained by a student in her class is twice the lowest marks plus10. The highest mark is 90. What is the lowest mark?
Om Sri Ram Om Sri Ram Om Sri Ram
1.A + B +C =
30cm, A + B = 20 Cm. Find B + c ?
Ans. 20 + c = 30, c= 30-20 = 10
2.If we add
10 to twice a number we get 50. Find the number
Ans. Let the
number = x, The twice number = 2x
An adding 1= = 2x + 10
By problem:
2x + 10 = 50, 2x = 40 There fore x = 20
3.If we
subtract 30 from three times a number, we get 90. Find the number.
Ans. Let the
number = x, Then The three times Number = 3x
On subtracting 30 = 3x – 30
By problem: 3x – 30 =100, 3x = 90 – 30 = 60
Ther fore x = 60/3 = 20
4.Find a
number which when multiplied by 8 and then reduced by 4 is equal to 68.
Sol. Let the
number = x, Then The multiply by 8 = 8x
By problem: 8x – 4 =68, 8x = 68 +4 = 72, x = 72/8 =9
5. Sum of two numbers is 100. If one exceeds the other by 6, find the
numbers.
Sol. Lat the
one number be=x, Then the other number =x-6
Sum of the numbers: x + x-6 = 2x - 6
By problem: 2x – 6 = 100, 2x = 100 +
6=106, x= 53
6.Sum of
three consecutive integers is 27. Find the integers.
Let the three integers be x, x+1, x+2
By problem+ 3x + 3=27, 3x = 27 -3= 24 x= 8
Therefore consecutiveintegers= 8,9,10
7.Find x
length 5x+4 and breath x-4 of the rectangle if its perimeter is 72m.
Sol:
P=2(L+B)= 2(5x + 4 + x – 4)= 12x
By problem: 12x = 72 , x = 72/12 =6
8. After 18
year. Rama’s age will become four times that of he present age. Find he present
age.
Let the
present age of Rama be x years
After 18
years Rama’s age = 4x
By problem :
x + 18 = 4x There fore 3x = 18, x= 6
9.langth of
a rectangle exceeds its breadth by 5m. If the perimeter of the rectangle is
100m. Find its length and breadth.
Sol. Breath =
x, length = x + 5
P= 2 (l + b) = 2(x + 5 +X) , 4x + 10
=100
There fore 4x = 90 x=90/4 =22.5
10.Rama Said “multiplying my number by 10 and adding 20
to it gives the same answer subtracting my number from 40. Find Rama’s number.
Sol. Let
Rama’s number be x
Multiplying by 10 and adding 20 to that number = 1ox +20
Subtracting
that number 40 =40 –x
By proble above two are equal
i.e = 10x + 20 = 40 – x , 11x = 20, x =
20/11
11. A number
is divided into two parts such that one part is 20 more than the other. if the
two parts in the ration 4: 5 Find the
number and the two parts.
Sol. Let one
part be x, Then the other part = x + 20
Ratio of these two parts= x + 20 : x = 4 : 5
X
+ 20 /x = 4/5, 5(x + 20)=4x, 5x + 100 = 4x, x = -100
12.A sum of
Rs. 5000 is to be given in the from of 75 prizes. If the prize money is either Rs 100 or Rs. 25. Find
the number of prizes of each type.
Sol. Let the
number of Rs. 100 prizes be x
The number of Rs. 25 prizes be = 75-x
,
Value of the prizes = 100 x +
(75-x)25 = 100x -25x+1875=0
By problem: 75x +1875 = 5000
:75x = 5000 – 1875 = 3125
X =
3125/75 = 41.6
13. x0
+ 2x0 + 3x0 = 180
Find three angles
6x = 180, x = 180/6 = 30
The
angles 300, 600, 900
14. I am a
number Tell my identity Take me two times over and add a forty six To reach a
century You still need five.
Let the number be x
Two times the number = 2x
On adding 46 = 2x + 46
BY problem: 2x + 46 = 100-5
2x = 95-46= 49 x= 49/2 = 24.5
15.The
teacher tells the class that the highest marks obtained by a student in her
class is twice the lowest marks plus10.
The highest mark is 90. What is
the lowest mark?
Let the
lowest marks of the class = x
Twice least
marks = 2x , on adding 2x + 10
By problem :
2x + 10 = 90, 2x = 80 , x = 40
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